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  1. Once you've done that, refresh this page to start using Wolfram|Alpha. sin^2 (x) Natural Language. Math Input. Extended Keyboard Examples Upload Random. Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals.

  2. The sin 2x formula is the double angle identity used for sine function in trigonometry. Trigonometry is a branch of mathematics where we study the relationship between the angles and sides of a right-angled triangle. There are two basic formulas for sin 2x: sin 2x = 2 sin x cos x (in terms of sin and cos) sin 2x = (2tan x) / (1 + tan 2 x) (in ...

  3. As many people have pointed out by now, $\sin^2 x$ is simply a "nickname" for $(\sin x)^2$. Therefore, $\sin^2\ 30 = (\sin 30)^2 = (1/2)^2 = 1/4$. As it happens, though, there is another useful thing we can say about $\sin^2 x$: $$\sin^2 x = (\sin x)^2 = \frac12 (1 - \cos (2 x)).$$ We can see this using the double-angle formula for cosines ...

  4. What Are Sin Squared x Formulas? Using one of the trigonometric identities, we have sin 2 x + cos 2 x = 1. Subtracting cos 2 x from both sides, we get sin 2 x = 1 - cos 2 x. Thus, one of the sin squared x formulas is, \ (\sin^2x = 1-\cos^2x\) Using one of the double angle formulas of cosine function, we have cos 2x = 1 - 2 sin 2 x.

  5. Revise trigonometric ratios of sine, cosine and tangent and calculate angles in right-angled triangles with this Bitesize GCSE Maths Edexcel guide.

  6. 3/1. 4/0. Given Triangle abc, with angles A,B,C; a is opposite to A, b opposite B, c opposite C: a/sin (A) = b/sin (B) = c/sin (C) c ^2 = a ^2 + b ^2 - 2ab cos (C) b ^2 = a ^2 + c ^2 - 2ac cos (B) a ^2 = b ^2 + c ^2 - 2bc cos (A) (Law of Cosines) (a - b)/ (a + b) = tan [ (A-B)/2] / tan [ (A+B)/2]

  7. The following (particularly the first of the three below) are called "Pythagorean" identities. sin 2 (t) + cos 2 (t) = 1. tan 2 (t) + 1 = sec 2 (t) 1 + cot 2 (t) = csc 2 (t) Note that the three identities above all involve squaring and the number 1. You can see the Pythagorean-Thereom relationship clearly if you consider the unit circle, where ...

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