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  1. Using Bitwise AND operator. The idea is to check whether the last bit of the number is set or not. If last bit is set then the number is odd, otherwise even. If a number is odd & (bitwise AND) of the Number by 1 will be 1, because the last bit would already be set. Otherwise it will give 0 as output.

  2. Write a function to check if the entered integer is odd or even. If the given number is odd, return "Odd". If the given number is even, return "Even". For example, for input 4, the output should be "Even". Check Code.

  3. Mar 23, 2015 · You can raise -1 to the power of n, and see if the number is 1 or -1: def isOdd(num): if type(num) not in [int, long]: return False. if ((-1)**num) == 1: return False.

  4. May 9, 2024 · In this Python tutorial, I will show even odd program in Python using function. I had to implement the functionality of checking whether a given number is even or odd in the advanced Python calculator, so I created a function that can take any number and tell if it is even or odd.

  5. def is_odd(num): # Return True or False, depending on if the input number is odd. # Odd numbers are 1, 3, 5, 7, and so on. # Even numbers are 0, 2, 4, 6, and so on.

  6. 2 days ago · Let's take a look at the python code that checks and displays odd numbers in the specified range. checkOddNumbers.py. # Function to check and display odd numbers in the range 1 to 10 def checkOddNumbers(): odd_numbers = [num for num in range(1, 11) if num % 2 != 0] return odd_numbers. # Driver program if __name__ == "__main__": # Call the ...

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  8. Aug 27, 2020 · Solution #1. def find(num): # code logic here. if num%2 == 0: numtype="even" else: numtype = "odd" return numtype. num = int(input('Enter the number: ')) # 1. take your input. numtype = find(num) # 2. call the find function. print('Given number is',numtype). # 3. print if the number is even or odd. Output:

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