Search results
- Dictionaryround/raʊnd/
adjective
- 1. shaped like a circle or cylinder: "she was seated at a small, round table" Similar
- 2. shaped like a sphere: "a round glass ball"
noun
- 1. a circular piece of something: "cut the pastry into rounds" Similar
- 2. an act of visiting a number of people or places in turn: "she did the rounds of her family to say goodbye"
adverb
- 1. so as to rotate or cause rotation; with circular motion: "a plane circled round overhead"
- 2. so as to rotate and face in the opposite direction: "he swung round to face her"
preposition
- 1. on every side of (a focal point): "the area round the school" Similar
- 2. so as to encircle (someone or something): "he wrapped the blanket round him"
verb
- 1. pass and go round (something) so as to move on in a changed direction: "the ship rounded the cape and sailed north"
- 2. alter (a number) to one less exact but more convenient for calculations: "we'll round the weight up to the nearest kilo"
Powered by Oxford Dictionaries
Dec 25, 2016 · 35. TypeError: type numpy.ndarray doesn't define round method. You tried applying round to numpy.ndarray. Apparently, this isn't supported. Try this, use numpy.round: rounded = [numpy.round(x) for x in predictions] x is numpy array. You can also try this: rounded = [round(y) for y in x for x in predictions]
Apr 23, 2022 · 2. You are only returning price in your function if type == 'P'. But for the branch type == 'C' there is no return statement. Maybe you mean: try: if type == "C": price = S*norm.cdf(d1, 0, 1) - K*np.exp(-r*T)*norm.cdf(d2, 0, 1) elif type == "P":
The documentation for the round () function states that you pass it a number, and the positions past the decimal to round. Thus it should do this: n = 5.59. round(n, 1) # 5.6. But, in actuality, good old floating point weirdness creeps in and you get: 5.5999999999999996. For the purposes of UI, I need to display 5.6.
Mar 1, 2022 · Round does not accept an iterator. If you're trying to calculate the median of the list and then round that value (as I would expect you are trying to do) you can use: ml=round(n.median(lower))
Oct 29, 2012 · You can see that PostgreSQL is expanding it in the output). You must cast the value to be rounded to numericto use the two-argument form of round. Just append ::numericfor the shorthand cast, like round(val::numeric,2). If you're formatting for display to the user, don't use round.
Mar 14, 2012 · int y = (int)x; // truncated to 55. C++11 also introduces std::round, which likely uses a similar logic of adding 0.5 to |x| under the hood (see the link if interested) but is obviously more robust. A follow up question might be why the float isn't stored as exactly 55. For an explanation, see this stackoverflow answer.
You are using the round function from base python on a spark Column object, which is not properly defined. Use the round function from pyspark.sql.functions instead: results = spark.createDataFrame([{'book_id': 148, 'user_id': 588, 'rating': 4, 'prediction': 3.953999}]) from pyspark.sql.functions import round # import the method here.
More than likely some of the labels you have in y_train are actually strings instead of numbers.sklearn and xgboost don't require the labels to be numeric.
Oct 3, 2012 · round is defined in ISO C++11, as it contains the ISO C99 standard library. round is not part of the ISO C++98, which uses the ISO C90 standard library. That's why it's not in namespace std for C++98. But g++ is (incorrectly) including the C99 headers, even when compiled with -std=c++98 -pedantic, which should disable all non-standard stuff:
Dec 18, 2019 · It seems to me that Excel always 'round up' when it needs to calculate numbers like 1.5, 2.5, 3.5, etc while R/Python will round to the nearest even number instead. Potentially there're other assumptions I'm not aware of which differentiate both Excel and R/Python. Is there any way to implement the exact round function from Excel in R? In Excel ...
