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      • The mass M of the object cancels, leaving an equation for g: g = GM r2. Substituting known values for Earth’s mass and radius (to three significant figures), g = (6.67 × 10 − 11N ⋅ m2 kg2) × 5.98 × 1024 kg (6.38 × 106 m)2, and we obtain a value for the acceleration of a falling body: g = 9.80 m / s2.
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  2. Substituting mg for \(F\) in Newton’s universal law of gravitation gives \[mg = G\dfrac{mM}{r^2}, \] where \(m\) is the mass of the object, \(M\) is the mass of Earth, and \(r\) is the distance to the center of Earth (the distance between the centers of mass of the object and Earth).

  3. Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

  4. For two bodies having masses m and M with a distance r between their centers of mass, the equation for Newton’s universal law of gravitation is F = G m M r 2 F = G m M r 2 where F is the magnitude of the gravitational force and G is a proportionality factor called the gravitational constant .

    • Tides
    • “Weightlessness” and Microgravity
    • The Cavendish Experiment: Then and Now
    • Section Summary
    • Glossary

    Ocean tides are one very observable result of the Moon’s gravity acting on Earth. Figure 5 is a simplified drawing of the Moon’s position relative to the tides. Because water easily flows on Earth’s surface, a high tide is created on the side of Earth nearest to the Moon, where the Moon’s gravitational pull is strongest. Why is there also a high ti...

    In contrast to the tremendous gravitational force near black holes is the apparent gravitational field experienced by astronauts orbiting Earth. What is the effect of “weightlessness” upon an astronaut who is in orbit for months? Or what about the effect of weightlessness upon plant growth? Weightlessness doesn’t mean that an astronaut is not being...

    As previously noted, the universal gravitational constant G is determined experimentally. This definition was first done accurately by Henry Cavendish (1731–1810), an English scientist, in 1798, more than 100 years after Newton published his universal law of gravitation. The measurement of G is very basic and important because it determines the str...

    Newton’s universal law of gravitation: Every particle in the universe attracts every other particle with a force along a line joining them. The force is directly proportional to the product of thei...
    Newton’s law of gravitation applies universally.

    gravitational constant, G:a proportionality factor used in the equation for Newton’s universal law of gravitation; it is a universal constant—that is, it is thought to be the same everywhere in the universe center of mass:the point where the entire mass of an object can be thought to be concentrated microgravity:an environment in which the apparent...

  5. Mar 12, 2024 · For two bodies having masses m and M with a distance r between their centers of mass, the equation for Newton’s universal law of gravitation is. F = GmM r2, where F is the magnitude of the gravitational force and G is a proportionality factor called the gravitational constant.

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  6. Aug 11, 2021 · Newton’s Law of Gravitation. Newton’s law of gravitation can be expressed as \[\vec{F}_{12} = G \frac{m_{1} m_{2}}{r^{2}} \hat{r}_{12} \label{13.1}\] where \(\vec{F}_{12}\) is the force on object 1 exerted by object 2 and \(\hat{r}_{12}\) is a unit vector that points from object 1 toward object 2.

  7. Newton s Law of Universal Gravitation is. (m1)g(m2)g. = G (1) r2 where (m1)g and (m2)g are the gravitational masses of two objects separated by a distance r and G is. constant (to be given below). F is the magnitude of the force between the two objects and the force is attractive.