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The “Electrolysis” Equation: Let us now combine the two laws of Faraday into one convenient equation that can be used in electrolysis problems. To produce w grams or (w/E) equivalents of an element by electrolysis, we need (w/E)×F Coulombs of charge to pass through the solution. Mathematically, Q = It =(w/E)F.
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Here are the answers to the textbook questions. All of the past paper questions and mark schemes, organised by topic. Practical Exam Questions (organised by required practical) and a powerpoint containing photos of all of the required practicals. Multiple Choice Practice Questions.
Here is the powerpoint used in class to introduce you to the course. This includes the topics that you need to learn for the test in the second week. Official definitions from exam mark schemes. All of the information below is from the GCSE Chemistry specification.
- Chemical Equations
- Subscripts and Coefficients Give Different Information
- Molar Mass
- Using Moles
- Mole Relationships
- Elemental Analyses
- How Many Cookies Can I Make?
- Theoretical Yield
- In a chemical equation, the substances to the left of the arrow are called the:
- When hydrocarbons are burned in air, they form:
Chemical equations are concise representations of chemical reactions.
• Subscripts tell the number of atoms of each element in a molecule. Subscripts and Coefficients Give Different Information Subscripts tell the number of atoms of each element in a molecule Coefficients tell the number of molecules.
By definition, a molar mass is the mass of 1 mol of a substance (i.e., g/mol). The molar mass of an element is the mass number for the element that we find on the periodic table. The formula weight (in amu’s) will be the same number as the molar mass (in g/mol).
Moles provide a bridge from the molecular scale to the real-world scale.
One mole of atoms, ions, or molecules contains Avogadro’s number of those particles. One mole of molecules or formula units contains Avogadro’s number times the number of atoms or ions of each element in the compound.
Compounds containing other elements are analyzed using methods analogous to those used for C, H and O.
You can make cookies until you run out of one of the ingredients. Once this family runs out of sugar, they will stop making cookies (at least any cookies you would want to eat). How Many Cookies Can I Make? • In this example the sugar would be the limiting reactant, because it will limit the amount of cookies you can make.
The theoretical yield is the maximum amount of product that can be made. In other words it’s the amount of product possible as calculated through the stoichiometry problem. This is different from the actual yield, which is the amount one actually produces and measures.
yields. reactants. products. coefficients. In a chemical equation, the substances to the left of the arrow are called the: yields. reactants. products. coefficients.
water and carbon dioxide. charcoal. methane. oxygen and water. When hydrocarbons are burned in air, they form: water and carbon dioxide. charcoal. methane. oxygen and water. The formula weight of
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Chemical equations are used to describe chemical reactions. chemical equation has the following elements: The chemical symbols for the reactants are placed on the left-land side of the equation and the chemical symbols for the products are placed on the right-hand side.
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Mole: The amount of substance that has the same number of particles (atoms, ions, molecules or electrons) as there are atoms in exactly 12 g of the 12C isotope. Molecular formula: The actual number of each type of atoms in a molecule.
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Oct 27, 2022 · Explain the form and function of a rate law. Use rate laws to calculate reaction rates. Use rate and concentration data to identify reaction orders and derive rate laws. As described in the previous module, the rate of a reaction is affected by the concentrations of reactants.
