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Milan, Indiana. Location of Milan in Ripley County, Indiana. Milan (/ ˈmaɪlɪn / MY-lin) [4] is a town in Franklin and Washington townships, Ripley County, in the U.S. state of Indiana. [2] The population was 1,899 at the 2010 census.
Milan is a town in Franklin and Washington townships, Ripley County, in the U.S. state of Indiana. Milan has about 1,900 residents. Mapcarta, the open map.
Milan is a township located in the county of Ripley in the U.S. state of Indiana. Its population at the 2010 census was 1,899 and a population density of 360 people per km². After 10 years in 2020 city had an estimated population of 1,833 inhabitants.
- United States of America
- 1,833 (2020)
- Ripley County
- Indiana (United States)
In 2022, Milan, IN had a population of 1.98k people with a median age of 44.4 and a median household income of $53,047. Between 2021 and 2022 the population of Milan, IN grew from 1,955 to 1,981, a 1.33% increase and its median household income declined from $56,250 to $53,047, a −5.69% decrease.
Milan is described as, "A town in Ripley County, one and a half miles from the Ohio & Mississippi Railroad, forty-two miles from Cincinnati, and eight from Versailles, the county seat.
Milan is a municipality in Ripley County, situated in the southeastern part of Indiana, USA. It is located approximately 90 miles southeast of Indianapolis and about 45 miles west of Cincinnati, Ohio. The town lies near the Laughery Creek, providing a scenic landscape typical of the region.
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Milan ( / ˈmaɪlɪn / MY-lin) is a town in Franklin and Washington townships, Ripley County, in the U.S. state of Indiana. The population was 1,899 at the 2010 census.
