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  1. Given a function y = f (x), the graph is concave up (convex) in the intervals where the second derivative of the function is positive. The graph is concave down (concave) in the intervals where...

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  2. Dec 21, 2020 · Let \(f(x)=x^3-3x+1\). Find the inflection points of \(f\) and the intervals on which it is concave up/down. Solution. We start by finding \(f'(x)=3x^2-3\) and \(f''(x)=6x\). To find the inflection points, we use Theorem \(\PageIndex{2}\) and find where \(f''(x)=0\) or where \(f''\) is undefined.

  3. Sep 16, 2022 · You can locate a function's concavity (where a function is concave up or down) and inflection points (where the concavity switches from positive to negative or vice versa) in a few simple steps. The following method shows you how to find the intervals of concavity and the inflection points of

  4. State the first derivative test for critical points. Use concavity and inflection points to explain how the sign of the second derivative affects the shape of a function’s graph. Explain the concavity test for a function over an open interval.

  5. If given a graph of f(x) or f'(x), determining concavity is relatively simple. Otherwise, the most reliable way to determine concavity is to use the second derivative of the function; the steps for doing so as well as an example are located at the bottom of the page. How to find concavity from the first derivative

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  7. If [latex]f''(x)[/latex] is positive on an interval, the graph of [latex]y=f(x)[/latex] is concave up on that interval. We can say that [latex]f[/latex] is increasing (or decreasing) at an increasing rate. If [latex]f''(x)[/latex] is negative on an interval, the graph of [latex]y=f(x)[/latex] is concave down on that interval.

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