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  1. State the first derivative test for critical points. Use concavity and inflection points to explain how the sign of the second derivative affects the shape of a function’s graph. Explain the concavity test for a function over an open interval.

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  3. Dec 21, 2020 · Interval 2, \((-1,0)\): For any number \(c\) in this interval, the term \(2c\) in the numerator will be negative, the term \((c^2+3)\) in the numerator will be positive, and the term \((c^2-1)^3\) in the denominator will be negative. Thus \(f''(c)>0\) and \(f\) is concave up on this interval.

  4. How do you describe the concavity of the graph and find the points of inflection (if any) for #f(x) = x^3 - 3x + 2#?

  5. If \( f''(x) \) is positive on an interval, the graph of \( y=f(x) \) is concave up on that interval. We can say that \(f\) is increasing (or decreasing) at an increasing rate. If \( f''(x) \) is negative on an interval, the graph of \( y=f(x) \) is concave down on that interval.

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  7. Dec 21, 2020 · If we are trying to understand the shape of the graph of a function, knowing where it is concave up and concave down helps us to get a more accurate picture. Of particular interest are points at which the concavity changes from up to down or down to up; such points are called inflection points.

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