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Step 1: Given f (x), find f (a), f (b), f (c), for x= a, b and c, where a < c < b. Where a and b are the points of interest. C is just any convenient point in between them. Step 2: Find the equation of the line that connects the points found for a and b. Step 3: Find that y-coordinate of the line from Step 2 at point C.
- 2 min
- Sal Khan
Jul 26, 2016 · Start practicing—and saving your progress—now: https://www.khanacademy.org/math/ap-c... Sal finds the intervals where g (x)=-x_+6x_-2x-3 is concave down/up by finding where its second ...
- 9 min
- 78.1K
- Khan Academy
Jan 30, 2013 · Sal introduces the concept of concavity, what it means for a graph to be "concave up" or "concave down," and how this relates to the second derivative of a function. Created by Sal Khan. Practice...
- 10 min
- 512.9K
- Khan Academy
State the first derivative test for critical points. Use concavity and inflection points to explain how the sign of the second derivative affects the shape of a function’s graph. Explain the concavity test for a function over an open interval.
Dec 21, 2020 · The important \(x\)-values at which concavity might switch are \(x=-1\), \(x=0\) and \(x=1\), which split the number line into four intervals as shown in Figure \(\PageIndex{7}\). We determine the concavity on each.
How do you know that if g"(-2) is negative over the whole interval? How do I know it's not crossing through 0 or discontinuous?
- 9 min
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