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Study with Quizlet and memorize flashcards containing terms like what is chemistry, define scientific method, what are the steps in carrying out the scientific method? and more.
- chapter 1 and 2 chemistry Flashcards
Study with Quizlet and memorize flashcards containing terms...
- chapter 1 and 2 chemistry Flashcards
Oct 11, 2024 · Study with Quizlet and memorize flashcards containing terms like Name two categories used to classify properties of matter, Name three states of matter, solid and more.
Study with Quizlet and memorize flashcards containing terms like Chemistry, Matter, How do Chemists Study Matter? and more.
- Table of Contents
- What Is Gay-Lussac’s Law?
- Formula and Derivation
- Examples of Gay-Lussac’s Law
- Solved Exercises on Gay-Lussac’s Law
Gay-Lussac’s law is a gas law which states that the pressure exerted by a gas (of a given mass and kept at a constant volume) varies directly with the absolute temperature of the gas. In other words, the pressure exerted by a gas is proportional to the temperature of the gas when the mass is fixed and the volume is constant. This law was formulated...
Gay-Lussac’s law implies that the ratio of the initial pressure and temperature is equal to the ratio of the final pressure and temperature for a gas of a fixed mass kept at a constant volume. This formula can be expressed as follows: (P1/T1) = (P2/T2) Where: 1. P1is the initial pressure 2. T1is the initial temperature 3. P2is the final pressure 4....
When a pressurized aerosol can (such as a deodorant can or a spray-paint can) is heated, the resulting increase in the pressure exerted by the gases on the container (owing to Gay-Lussac’s law) can result in an explosion. This is the reason why many pressurized containers have warning labels stating that the container must be kept away from fire an...
Exercise 1
The pressure of a gas in a cylinder when it is heated to a temperature of 250K is 1.5 atm. What was the initial temperature of the gas if its initial pressure was 1 atm? Given, Initial pressure, P1= 1 atm Final pressure, P2= 1.5 atm Final temperature, T2= 250 K As per Gay-Lussac’s Law, P1T2 = P2T1 Therefore, T1 = (P1T2)/P2= (1*250)/(1.5) = 166.66 Kelvin.
Exercise 2
At a temperature of 300 K, the pressure of the gas in a deodorant can is 3 atm. Calculate the pressure of the gas when it is heated to 900 K. Initial pressure, P1= 3 atm Initial temperature, T1= 300K Final temperature, T2= 900 K Therefore, final pressure (P2) = (P1T2)/T1= (3 atm*900K)/300K = 9 atm. To learn more about Gay-Lussac’s law and other gas laws, such as Charles’ law, register with BYJU’S and download the mobile application on your smartphone.
- 9 min
1.3 Physical and Chemical Properties. All substances have distinct physical and chemical properties, and may undergo physical or chemical changes. Physical properties, such as hardness and boiling point, and physical changes, such as melting or freezing, do not involve a change in the composition of matter.
In this text, you will begin to explore the history of the formal study of physics, beginning with natural philosophy and the ancient thinkers from the Middle East and the Mediterranean, and leading up through a review of Sir Isaac Newton and the laws of physics that bear his name.
Define chemistry in relation to other sciences. Identify the general steps in the scientific method. Chemistry is the study of matter—what it consists of, what its properties are, and how it changes.
