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For each problem, find the x-coordinates of all points of inflection, find all discontinuities, and find the open intervals where the function is concave up and concave down. 1)
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Determine where the given function is increasing and decreasing. Find where its graph is concave up and concave down, the relative extrema, inflection points and sketch the graph of the function, A series of free Calculus Videos.
Increasing and Decreasing Functions, Concavity 1. Suppose f(x) = (x 31)(x 4)(x 9) = x 14x2 + 49x 36: (a) Find the intervals on which f(x) is increasing and the intervals on which f(x) is decreasing. (b) Find the intervals on which f(x) is concave up and the intervals on which f(x) is concave down. 2. Suppose g0(x) = (x 1)(x 4)(x 9) = x3 14x2 ...
Worksheet 22: Concavity Russell Buehler b.r@berkeley.edu www.xkcd.com 1. If you haven’t already, label the local maxima/minima, absolute maximum/minimum, in ection points, and where the graph is concave up or concave down. 2. What is the rst derivative test? What is the second derivative test?
Review your knowledge of concavity of functions and how we use differential calculus to analyze it.
First, we compute $\ds f'(x)=3x^2-1$ and $f''(x)=6x$. Since $f''(0)=0$, there is potentially an inflection point at zero. Since $f''(x)>0$ when $x>0$ and $f''(x) 0$ when $x 0$ the concavity does change from down to up at zero, and the curve is concave down for all $x 0$ and concave up for all $x>0$. $\square$
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What is the problem in concavity practice 3?
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Why do we need to know where a graph is concave?
Concave up because the rate of change is increasing over equal‐length input‐value intervals. Concave down because the rate of change is decreasing over equal‐length input‐value intervals.
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