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researchgate.net
- Concavity in a curve refers to its curvature, or the way it bends. If a curve is concave up, it opens upward like a cup, while if it's concave down, it opens downward like a frown. Mathematically, a curve is concave up if its second derivative is positive, and concave down if its second derivative is negative.
www.geeksforgeeks.org/concavity-and-points-of-inflection/
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Dec 21, 2020 · Definition Concave Up and Concave Down. Let \(f\) be differentiable on an interval \(I\). The graph of \(f\) is concave up on \(I\) if \(f'\) is increasing. The graph of \(f\) is concave down on \(I\) if \(f'\) is decreasing. If \(f'\) is constant then the graph of \(f\) is said to have no concavity.
Given any x 1 or x 2 on an interval such that x 1 < x 2, if f (x 1) > f (x 2), then f (x) is decreasing over the interval. In the graph of f' (x) below, the graph is decreasing from (-∞, 1) and increasing from (1, ∞), so f (x) is concave down from (-∞, 1) and concave up from (1, ∞).
Sal introduces the concept of concavity, what it means for a graph to be "concave up" or "concave down," and how this relates to the second derivative of a function.
Theorem 3. Let C R be an open interval. 1. f: C!R is concave i for any a;b;c2C, with a<b<c, f(b) f(a) b a f(c) f(b) c b; and, f(b) f(a) b a f(c) f(a) c a: For strict concavity, the inequalities are strict. 2. f: C!R is convex i for any a;b;c2C, with a<b<c, f(b) f(a) b a f(c) f(b) c b; and, f(b) f(a) b a f(c) f(a) c a:
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Dec 21, 2020 · Example \(\PageIndex{1}\) Describe the concavity of \( f(x)=x^3-x\). Solution. The first dervative is \( f'(x)=3x^2-1\) and the second is \(f''(x)=6x\). Since \(f''(0)=0\), there is potentially an inflection point at zero.
If f ′ (x) is negative on an interval, the graph of y = f(x) is decreasing on that interval. The second derivative tells us if a function is concave up or concave down. If f ″ (x) is positive on an interval, the graph of y = f(x) is concave up on that interval.
Example 5.4.1 Describe the concavity of $\ds f(x)=x^3-x$. First, we compute $\ds f'(x)=3x^2-1$ and $f''(x)=6x$. Since $f''(0)=0$, there is potentially an inflection point at zero.