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Solution: Elastic collisions conserve both momentum and kinetic energy. Inelastic collisions conserve only momentum. However, total energy is conserved, since some kinetic energy will be converted into other forms. 2. Particle A, which is stationary, radioactively decays to create particle B and an weighs only 1.5% of particle B. particle. The.
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Answer: See table above. Before Collision: 1 kg) * (+2 m/s) + (1 kg) * (1 m/s ) = 3 kg m/s. After Collision: (1 kg) * (1 m/s) + (1 kg) * (2 m/s ) = 3 kg m/s. The total system momentum is the same before and after the collision. Thus, momentum is conserved and there is no net external impulse on the system.
The document discusses conservation of momentum and the two types of collisions - elastic and inelastic. It provides definitions and examples to illustrate how to apply the conservation of momentum equation to calculate unknown velocities in collision situations.
Several examples analyze 2D collisions between cars at intersections and 1D collisions between balls and particles, requiring vector addition and subtraction to determine momentum and velocity values.
Calculate the rock’s momentum as it strikes the ground. 1. A force of 20.0 N is applied to a 3.00 kg object for 4.00 seconds. Calculate the impulse experienced by the object. 2. A 1200 kg car traveling at 20.0 m/s speeds up to 30.0 m/s. What is the impulse experienced by the car? 3. A 1500 kg car accelerates from 55.0 km/h to 90.0 km/h.
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In the next activity you will make qualitative observations using two carts of equal mass moving toward each other at the same speed. You will observe momentum changes for several types of interactions, including an elastic and inelastic col-lision and an explosion.
