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  1. Elastic Collisions in Two Dimensions Cheat Sheet. In Chapter 4 of FM1, you learnt to solve problems involving the direct collision of particles. We will extend this further and learn to solve problems where the particles do not necessary move towards each other along a straight line. This is known as an oblique impact.

  2. Apr 2, 2019 · Momentum and Collisions, Practice B m = 0.50 kg vi = 15 m/s to the right ∆t = 0.020 s − (0.50 kg)(0 m/s) kg)(15 m/s) = ⎯mvf ⎯ mvi = ⎯⎯⎯⎯ −(0.50 to the right ∆ t 0.020 s = −3.8 × 102 N to the right vf = 0 m/s F = 3.8 × 102 N to the left m = 82 kg ∆y = −3.0 m ∆t = 0.55 s

  3. Combine the resolved velocities post-collision to calculate the final velocity vector. Everything you need to know about Elastic Collisions in Two Dimensions: Successive Oblique Impacts for the A Level Further Mathematics Edexcel exam, totally free, with assessment questions, text & videos.

  4. The Solutions Guide includes all the PDFs and source documents (MS Word files) of the Think Sheets at the Curriculum Corner, along with answers, explanations, and solutions, and a broader set of licensing rights.

  5. For example: The table top could be marked with a grid of squares (or graph paper) for improved position determination. The size of the ball bearings could be reduced so that their position is more accurately determined, and also so that the trajectories change more on collision, reducing the percentage errors in trajectory direction determination.

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  6. Most candidates knew how to answer part (c) but the last two parts were more demanding and required clear and careful thinking to achieve the correct answers. A common error was to assume that the velocity of P perpendicular to CB was the same both before and after P hit the second wall.

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  8. In the game of golf a stationary ball is hit by a club. One of the aims of the game is to land the ball on a patch of ground called the green. The graph shows how the force F exerted by the club on the ball varies with time t as the ball is hit. State why the area under the graph represents impulse. (1)

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