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Apr 10, 2021 · Let the force (F) act on the body and displace it by 'S'. Then work done by this force equals change in Kinetic energy. Let initial velocity be u and final velocity be v. Now, Work done by F = Δ Δ KE. F.S = 12 1 2 mv 2 2 - 12 1 2 mu 2 2 ... i. Also from Newton's second law : F = ma.
Velocity, acceleration and distance. This equation applies to objects in uniform acceleration: (final velocity) 2 - (initial velocity) 2 = 2 × acceleration × distance. \ (v^2 - u^2 = 2~a~s ...
Deriving the equations of kinematics - equations of motion from scratch. v = u + at; s = ut + 1/2 at²; v² = u² + 2as. Worked examples covering the three equations. Extra harder questions for practice - with answers. An interactive applet to practise distance/time, velocity/time and acceleration/time graphs.
v^2=u^2 + 2as u=12 a=-3 s = 18 Find v. First we can plug in the values we already know into the equation. we would get: V 2 = 12 2 + (2 x -3 x 18) then we would seperate the two multiplications on the right hand side12 x 12 = 144 2 x -3 x 18 = -6 x 18 = -108. Then we can plug these answers back into the equation. v 2 = 144 -108.
1.3 - Mechanics 1.3.1 - Equations of motion When an object is moving at uniform acceleration , you can use the following formulas: =u +av t =(u 2+v)s t =us t + 2 at 2 v 2 =u2+2as Where s = displacement, u = initial velocity, v = final velocity, a = acceleration, t = time.
Apr 16, 2024 · Our 3 equations of motion are. v = u + at. s = ut + 1 / 2at 2. v 2 - u 2 = 2as. Let's suppose an object with initial velocity u to final velocity v in time t. Let's derive all 3 equations. Here, Initial velocity = u = OA = CD. Final velocity = v = BD.
Dec 31, 2023 · v = u + at s= ut + ½at 2 v 2 = u 2 + 2as. In this scenario, the body is vertically projected upwards at 90 degrees to the ground with an initial velocity u. The final velocity v is 0 at the point where the object reaches maximum altitude and becomes stationary before falling back to Earth.
