Search results
Velocity, acceleration and distance. This equation applies to objects in uniform acceleration: (final velocity) 2 - (initial velocity) 2 = 2 × acceleration × distance. \ (v^2 - u^2 = 2~a~s ...
Oct 13, 2023 · Calculate final velocity as a function of initial velocity, acceleration and displacement using v^2 = u^2 + 2as. Solve for v, u, a or s; final velocity, initial velocity, acceleration ar displacement.
Deriving the equations of kinematics - equations of motion from scratch. v = u + at; s = ut + 1/2 at²; v² = u² + 2as. Worked examples covering the three equations. Extra harder questions for practice - with answers. An interactive applet to practise distance/time, velocity/time and acceleration/time graphs.
2 at2 v2=u2+2as s= 1 2 (u+v)t s=vt ... 3ms−1 4ms−1 5kg 2kg 1ms−1 vms−1 Before: After: m1u1+m2u2=m1v1+m2v2 5(3)+2(−4)=5(1)+2(v) 2=2(v) v=1ms−1.
For an object that has an initial velocity u and that is moving in a straight line with constant acceleration a, the following equations connect the final velocity v and displacement s in a given time t. Note: These equations cannot be used if the acceleration is not constant.
Another equation of motion states v2 = u2 +2as. As before, v = final speed, u = initial speed, a = acceleration, s = distance travelled. Example Suppose a stone is dropped from a cliff which is 100m high. Because the stone is simply dropped, rather than thrown, its initial speed is zero, and so u = 0. Its acceleration will be the acceleration
In this equation we can see that both v^2 and u^2 are independent of s. So, as v^2 is already on the other side of 's', i.e. it is on the Left Hand Side, we shall start by subtracting u^2 from both sides of the equation.
