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Velocity, acceleration and distance. This equation applies to objects in uniform acceleration: (final velocity) 2 - (initial velocity) 2 = 2 × acceleration × distance. \ (v^2 - u^2 = 2~a~s ...
at 2 v 2 =u2+2as Where V = displacement, X = initial velocity, Y = final velocity, D = acceleration, W = time. When approaching questions which require the use of these formulas, it is useful to write out the
3 - Kinematics 3.1 - Equations of Motion Distance - The distance travelled by an object is a scalar quantity and describes the amount of ground the object has covered. Displacement (s) - The overall distance travelled from the starting position (includes a direction and so it is a vector quantity).
If any three of the five quantities are known, then the other two may be calculated using the following four equations: v = u + at. x = ut + ½at 2. x = (u+v) ÷ 2 × t. v 2 = u 2 + 2as. The...
Apr 10, 2021 · Multiplying both sides by 2 and cancelling m on both sides. 2a.S = v $^2$ - u $^2$ Thus. v $^2$ = u $^2$ + 2aS [QED]
Mar 26, 2022 · Harder example questions for V^2 = U^2 + 2as. With full walk through solutions.
- 9 min
- 321
- Williams Physics Education
Deriving the equations of kinematics - equations of motion from scratch. v = u + at; s = ut + 1/2 at²; v² = u² + 2as. Worked examples covering the three equations. Extra harder questions for practice - with answers. An interactive applet to practise distance/time, velocity/time and acceleration/time graphs.
