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Let's sum that up to form the most essential projectile motion equations: 1. Launching the object from the ground (initial height h = 0): Horizontal velocity component: V x = V 0 cos α. V_\mathrm x = V_0 \cos \alpha V x = V 0 cosα. Vertical velocity component: V y = V 0 sin α − g t.
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The magnitudes of the components of displacement s → s → along these axes are x and y. The magnitudes of the components of velocity v → v → are v x = v cos θ and v y = v sin θ, v x = v cos θ and v y = v sin θ, where v is the magnitude of the velocity and θ is its direction relative to the horizontal, as shown in Figure 4.12.
Our calculator finds that v r e s = 16.55 km/h v_{\rm res} = 16.55\, \text{km/h} v res = 16.55 km/h and θ r e s = 25 ° \theta_{\rm res} = 25\degree θ res = 25°. It also shows the absolute values of the x and y components of the resultant velocity vector. You can check your results using the formulas below:
Oct 21, 2023 · distance = speed x time. Rate and speed are similar since they both represent some distance per unit time like miles per hour or kilometers per hour. If rate r is the same as speed s, r = s = d/t. You can use the equivalent formula d = rt which means distance equals rate times time. distance = rate x time. To solve for speed or rate use the ...
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The vector equation is →vPG = →vPA + →vAG, where P = plane, A = air, and G = ground. From the geometry in Figure 4.6.6, we can solve easily for the magnitude of the velocity of the plane with respect to the ground and the angle of the plane’s heading, θ. Figure 4.6.6: Vector diagram for Equation 4.6.2 showing the vectors →vPA, →vAG ...